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Trigonometry: all learning resources

9709 Pure Mathematics 1 · Maths4U Original

Trigonometry — Maths4U Original

Learn the method, study an example, then explain your reasoning in an exam-style problem. Work on paper before opening the solution and compare each step with the marking guidance.

Trigonometric equations on a stated interval

Find all angle branches, using the full transformed interval and the original domain.

Notes

Before you start: use exact values and inverse functions, and recognise each ratio's period.

For integer n, if \(\sin u=a\) and α=arcsin a, the families are \(u=\alpha+2n\pi\) and \(u=\pi-\alpha+2n\pi\). If \(\cos u=a\) and α=arccos a, use \(u=\pm\alpha+2n\pi\). These require |a|≤1. Duplicate angles at extreme values are counted once.

For \(\tan u=a\), use \(u=\arctan a+n\pi\), retaining excluded cosine-zero values. Calculator inverses return principal values, not a complete interval solution.

The principal output ranges are \([-\pi/2,\pi/2]\) for arcsine, \([0,\pi]\) for arccosine, and \((-\pi/2,\pi/2)\) for arctangent.

When u=kx+c, transform the entire x-interval into a u-interval first, find every branch in it, and transform back. Reverse inequalities if dividing by a negative coefficient. Check open/closed endpoints and substitute candidates into the original equation.

The line y=1/2 meets sine at π/6 and 5π/6 in one full turn; a principal value alone misses the second point.

Recall later

\(\cos x=0\) has x=π/2,3π/2 on \(0\le x<2\pi\); \(\tan x\) is undefined at those same points.

Common mistakes

  • Giving only the inverse-calculator value.
  • Solving for 2x only between 0 and 2π when x spans that interval.
  • Mixing a degree period with radian inputs.

Three worked examples

Example 1

Solve \(\sin x=-\sqrt3/2\) for \(0\le x<2\pi\).

Show the reasoning

The reference angle is π/3. Sine is negative in quadrants III and IV, giving \(x=4\pi/3,5\pi/3\).

Example 2

Solve \(\cos(2x)=1/2\) for \(0\le x<2\pi\).

Show the reasoning

The doubled angle runs through \(0\le2x<4\pi\). It has values π/3,5π/3,7π/3,11π/3. Dividing by 2 gives x=π/6,5π/6,7π/6,11π/6.

Example 3

Solve \(\tan(x-\pi/6)=0\) for \(0\le x<2\pi\).

Show the reasoning

Tangent is zero at integer multiples of π. Thus x=π/6+nπ. The permitted values are π/6 and 7π/6.

Short practice with answer checking

Original exam-style problems

M4U-ORIG-TRIG-007 · 7 marks

A shifted, doubled sine argument

Transfer the full interval, find all branches and transform back.

This problem is being prepared for publication.

M4U-ORIG-TRIG-008 · 7 marks

Tangent: period, exclusions and a false rule

Solve a shifted tangent equation and disprove an invalid distributive claim.

This problem is being prepared for publication.

Topic practice · Full topic bank

Next skill: Trigonometric equations that become quadratics →