A particle P travels in a straight line. It passes through the point O of the line with velocity 5 m s-1 at time t = 0, where t is in seconds. P's velocity after leaving O is given by
(0.002t3 - 0.12t2 + 1.8t + 5) m s-1.
The velocity of P is increasing when 0 < t < T1 and when t > T2, and the velocity of P is decreasing when T1 < t < T2.
A particle starts at a point O and moves along a straight line. Its velocity t s after leaving O is \((1.2t - 0.12t^2)\) m s-1. Find the displacement of the particle from O when its acceleration is 0.6 m s-2.
A vehicle is moving in a straight line. The velocity \(v\) m s-1 at time \(t\) s after the vehicle starts is given by
\(v = A(t - 0.05t^2) \quad \text{for} \; 0 \leq t \leq 15,\)
\(v = \frac{B}{t^2} \quad \text{for} \; t \geq 15,\)
where \(A\) and \(B\) are constants. The distance travelled by the vehicle between \(t = 0\) and \(t = 15\) is 225 m.
A motorcyclist starts from rest at A and travels in a straight line. For the first part of the motion, the motorcyclistโs displacement x metres from A after t seconds is given by x = 0.6t2 - 0.004t3.
A particle P starts from rest at the point A at time t = 0, where t is in seconds, and moves in a straight line with constant acceleration a m s-2 for 10 s. For 10 โค t โค 20, P continues to move along the line with velocity v m s-1, where v = \(\frac{800}{t^2} - 2\). Find
A particle P travels in a straight line, starting at rest from a point O. The acceleration of P at time t s after leaving O is denoted by a m/s2, where
\(a = 0.3t^{\frac{1}{2}}\) for \(0 \leq t \leq 4\),
\(a = -kt^{-\frac{3}{2}}\) for \(4 < t \leq T\),
where k and T are constants.
A particle P travels in a straight line from A to D, passing through the points B and C. For the section AB the velocity of the particle is \((0.5t - 0.01t^2)\) m s\(^{-1}\), where \(t\) is the time after leaving A.
An object P travels from A to B in a time of 80 s. The diagram shows the graph of v against t, where v m s-1 is the velocity of P at time t s after leaving A. The graph consists of straight line segments for the intervals 0 โค t โค 10 and 30 โค t โค 80, and a curved section whose equation is v = -0.01t2 + 0.5t - 1 for 10 โค t โค 30. Find

The velocity of a particle at time t seconds after it starts from rest is v m/s, where \(v = 1.25t - 0.05t^2\). Find
A motorcyclist starts from rest at A and travels in a straight line until he comes to rest again at B. The velocity of the motorcyclist t seconds after leaving A is v m s-1, where v = t - 0.01t^2. Find
A particle P starts from rest at O and travels in a straight line. Its velocity v m s-1 at time t s is given by v = 8t - 2t^2 for 0 โค t โค 3, and v = \frac{54}{t^2} for t > 3. Find
A particle P moves along the x-axis in the positive direction. The velocity of P at time t s is 0.03t2 m sโ1. When t = 5 the displacement of P from the origin O is 2.5 m.
A particle starts from rest at the point A and travels in a straight line until it reaches the point B. The velocity of the particle t seconds after leaving A is v m s-1, where v = 0.009t^2 - 0.0001t^3. Given that the velocity of the particle when it reaches B is zero, find
A particle P moves in a straight line that passes through the origin O. The velocity of P at time t seconds is v m s-1, where v = 20t - t^3. At time t = 0 the particle is at rest at a point whose displacement from O is -36 m.
A particle moves in a straight line. Its displacement t seconds after leaving the fixed point O is x metres, where \(x = \frac{1}{2}t^2 + \frac{1}{30}t^3\). Find
A particle P starts to move from a point O and travels in a straight line. At time t s after P starts to move its velocity is v m s-1, where v = 0.12t - 0.0006t2.
A particle P moves in a straight line through a point O. The velocity v ms-1 of P, at time t s after passing O, is given by
\(v = \frac{9}{4} + \frac{b}{(t+1)^2} - ct^2,\)
where b and c are positive constants. At t = 5, the velocity of P is zero and its acceleration is \(-\frac{13}{12}\) ms-2.
\((a) Show that b = 9 and find the value of c.\)
\((b) Given that the velocity of P is zero only at t = 5, find the distance travelled in the first 10 seconds of motion.\)
A particle P moves in a straight line. The velocity v m/s-1 at time t seconds is given by
\(v = 0.5t\) for \(0 \leq t \leq 10\),
\(v = 0.25t^2 - 8t + 60\) for \(10 \leq t \leq 20\).
(a) Show that there is an instantaneous change in the acceleration of the particle at \(t = 10\).
(b) Find the total distance covered by P in the interval \(0 \leq t \leq 20\).
A curve \(C\) has polar equation \(r=2a\cos\left(2\theta+\frac{\pi}{2}\right)\), for \(0\le\theta\lt2\pi\), where \(a\) is a positive constant.
(i) Show that \(r=-2a\sin2\theta\) and sketch \(C\).
(ii) Deduce that the Cartesian equation of \(C\) is \((x^2+y^2)^{3/2}=-4axy\).
(iii) Find the area of one loop of \(C\).
(iv) Show that, at the points other than the pole at which a tangent to \(C\) is parallel to the initial line, \(2\tan\theta=-\tan2\theta\).
The curve C has polar equation \(r = \theta e^{\frac{1}{8}\theta}\), for \(0 \leq \theta \leq 2\pi\).
(a) Sketch C.
(b) Find the area of the region bounded by C and the initial line, giving your answer in the form \((p\pi^2 + q\pi + r)e^{\frac{1}{2}\pi} + s\), where \(p, q, r\) and \(s\) are integers to be determined.
(c) Show that, at the point of C furthest from the initial line,
\(\theta \cos \theta + \left( \frac{1}{8} \theta + 1 \right) \sin \theta = 0\)
and verify that this equation has a root between 5 and 5.05.