Maths4U
Menu

Exam-Style Problem

Back to Velocity as the Integral of Acceleration with Respect to Time
Browsing as Guest. Progress, bookmarks and attempts are disabled. Log in to track your work.
9709 P41 - Jun 2010 - Q7
3783

A vehicle is moving in a straight line. The velocity \(v\) m s-1 at time \(t\) s after the vehicle starts is given by

\(v = A(t - 0.05t^2) \quad \text{for} \; 0 \leq t \leq 15,\)

\(v = \frac{B}{t^2} \quad \text{for} \; t \geq 15,\)

where \(A\) and \(B\) are constants. The distance travelled by the vehicle between \(t = 0\) and \(t = 15\) is 225 m.

  1. Find the value of \(A\) and show that \(B = 3375\).
  2. Find an expression in terms of \(t\) for the total distance travelled by the vehicle when \(t \geq 15\).
  3. Find the speed of the vehicle when it has travelled a total distance of 315 m.
No problems left in this filter.
Back to Velocity as the Integral of Acceleration with Respect to Time