One card is chosen from a pack of 52 cards.
Let:
- \(A\): the card is a face card
- \(B\): the card is a king
There are 12 face cards and 4 kings.
Every king is also a face card.
So:
\[
P(B \mid A)=\frac{P(A \cap B)}{P(A)}
=\frac{4/52}{12/52}
=\frac{1}{3}
\]
Therefore, if we already know the card is a face card, the probability that it is a king is \(\frac{1}{3}\).