A biased coin has probability \(p=0.6\) of landing heads.
The coin is tossed \(n=5\) times.
Let \(X\) be the number of heads.
\(X \sim B(5,0.6)\)
Find \(P(X=3)\).
Step 1: Substitute into formula
\[
P(X=3) = \binom{5}{3}(0.6)^3(0.4)^2
\]
Step 2: Calculate
\[
\binom{5}{3} = 10
\]
\[
P(X=3) = 10(0.216)(0.16)
\]
\[
P(X=3) = 0.3456
\]