The binomial distribution models the number of successes in a fixed number of independent trials.
A binomial experiment has four conditions:
If a random variable \(X\) counts the number of successes:
\(X \sim B(n,p)\)
The probability of exactly \(r\) successes is:
P(X=r)=\binom{n}{r}p^r(1-p)^{n-r}If \(X \sim B(n,p)\):
A biased coin has probability \(p=0.6\) of landing heads.
The coin is tossed \(n=5\) times.
Let \(X\) be the number of heads.
\(X \sim B(5,0.6)\)
Find \(P(X=3)\).
Step 1: Substitute into formula
\[ P(X=3) = \binom{5}{3}(0.6)^3(0.4)^2 \]Step 2: Calculate
\[ \binom{5}{3} = 10 \] \[ P(X=3) = 10(0.216)(0.16) \]If \(X \sim B(20,0.3)\):
Mean:
\[ \mu = np = 20(0.3) = 6 \]Variance:
\[ \sigma^2 = np(1-p) = 20(0.3)(0.7) = 4.2 \]Standard deviation:
\[ \sigma = \sqrt{4.2} \approx 2.05 \]