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Logarithmic equations can be solved by using logarithm laws or by changing the equation into exponential form.
For logarithms, remember:
Also:
A logarithm is only defined when its argument is positive.
Always check that your final answers make every logarithm valid.
Example: Solve
Combine the logarithms:
\[ \log\bigl(x(x-3)\bigr)=1 \]
If the logarithm is base 10, then:
\[ x(x-3)=10^1=10 \]
\[ x^2-3x-10=0 \] \[ (x-5)(x+2)=0 \]
So \(x=5\) or \(x=-2\).
Check the restriction:
If the bases are the same, then the arguments are equal:
\[ 2x+1=7 \] \[ 2x=6 \] \[ x=3 \]
Rewrite in exponential form:
\[ x+1=2^3 \] \[ x+1=8 \] \[ x=7 \]
Use the subtraction law:
\[ \log\left(\frac{x+4}{x}\right)=\log 2 \]
So:
\[ \frac{x+4}{x}=2 \] \[ x+4=2x \] \[ x=4 \]
Check: \(x>0\), so the answer is valid.
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