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Circular measure — Circular measure review 100 problems

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Year 12 (9709) — Circular Measure Review

Use radians for all circular-measure formulas unless stated otherwise.


1) Radian recap

Full circle: \(2\pi\) rad, half: \(\pi\) rad, quarter: \(\tfrac{\pi}{2}\) rad. Conversion: \( \;x^\circ = x\cdot \dfrac{\pi}{180}\text{ rad}\), \(\;\; y\text{ rad} = y\cdot \dfrac{180}{\pi}^\circ\).

Example — Convert \( 150^\circ \) to radians \[ 150^\circ = 150\cdot \frac{\pi}{180}=\frac{5\pi}{6}\text{ rad}. \]

2) Arc length

For a circle of radius \(r\) with central angle \(\theta\) (in radians): \[ \text{Arc length } \ell = r\theta. \]

Example — Find arc length for \(r=7\text{ cm}\), \(\theta=\tfrac{2\pi}{3}\) \[ \ell = r\theta = 7\cdot \frac{2\pi}{3}=\frac{14\pi}{3}\text{ cm}\;\;(\approx 14.66\text{ cm}). \]

3) Sector: area and perimeter

Area of a sector: \[ A_{\text{sector}}=\frac{1}{2}r^{2}\theta. \] Perimeter of a sector (two radii + arc): \[ P_{\text{sector}}=2r+r\theta. \]

Example — \(r=5\text{ cm}\), \(\theta=1.2\text{ rad}\) \[ A=\tfrac12\cdot 5^{2}\cdot 1.2=15\text{ cm}^2,\qquad P=2\cdot 5 + 5\cdot 1.2 = 10+6=16\text{ cm}. \]

4) Segment (minor): area and perimeter

Segment area (sector minus isosceles triangle): \[ A_{\text{seg}}=\frac{1}{2}r^{2}\,\big(\theta-\sin\theta\big). \] Chord length for angle \(\theta\): \[ c=2r\sin\!\left(\frac{\theta}{2}\right). \] Segment perimeter (arc + chord): \[ P_{\text{seg}}=r\theta + 2r\sin\!\left(\frac{\theta}{2}\right). \]

Example — \(r=9\text{ cm}\), \(\theta=1.4\text{ rad}\) \[ A_{\text{seg}}=\tfrac12\cdot 9^{2}\,(1.4-\sin 1.4) =40.5\,(1.4-0.9854) \approx 40.5\cdot 0.4146 \approx 16.8\text{ cm}^2. \] \[ c=2\cdot 9 \sin(0.7)\approx 18\cdot 0.645=11.61\text{ cm}. \] \[ P_{\text{seg}}=r\theta+c=9\cdot 1.4 + 11.61 \approx 12.6+11.61=24.21\text{ cm}. \]

5) Right triangles — SOHCAHTOA

For an acute angle \(\theta\) in a right triangle: \[ \sin\theta=\frac{\text{opp}}{\text{hyp}},\quad \cos\theta=\frac{\text{adj}}{\text{hyp}},\quad \tan\theta=\frac{\text{opp}}{\text{adj}}. \]

Example — hyp = 13, adj = 5, find \(\cos\theta\) and \(\sin\theta\) \[ \cos\theta=\frac{5}{13},\qquad \sin\theta=\sqrt{1-\cos^{2}\theta}=\sqrt{1-\frac{25}{169}}=\frac{12}{13}. \]

6) Sine Rule

For any triangle \(ABC\) with sides \(a,b,c\) opposite angles \(A,B,C\): \[ \frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}. \] Use when you have a pair (side with its opposite angle).

Example — Given \(A=40^\circ\), \(B=65^\circ\), \(a=7.2\text{ cm}\), find \(b\) First \(C=180^\circ-40^\circ-65^\circ=75^\circ\). Then \[ \frac{a}{\sin A}=\frac{b}{\sin B} \Rightarrow b=\frac{\sin 65^\circ}{\sin 40^\circ}\cdot 7.2 \approx \frac{0.9063}{0.6428}\cdot 7.2 \approx 10.16\text{ cm}. \]

7) Cosine Rule

For side \(a\) opposite angle \(A\): \[ a^{2}=b^{2}+c^{2}-2bc\cos A \] (and cyclic permutations). Use for SAS or SSS problems.

Example — \(b=8\), \(c=11\), included angle \(A=52^\circ\). Find \(a\) \[ a^{2}=8^{2}+11^{2}-2\cdot 8\cdot 11\cos 52^\circ =64+121-176\cos 52^\circ. \] With \(\cos 52^\circ\approx 0.6157\): \[ a^{2}\approx 185-176(0.6157)=185-108.36=76.64 \Rightarrow a\approx 8.76. \]

8) Area of a triangle

If two sides \(a,b\) and the included angle \(C\) are known: \[ \text{Area}=\frac{1}{2}ab\sin C. \]

Example — \(a=9\), \(b=12\), \(C=35^\circ\) \[ \text{Area}=\tfrac12\cdot 9\cdot 12\cdot \sin 35^\circ =54\cdot 0.574\approx 31.0\text{ (square units)}. \]

9) Mixed application (arc, chord, triangle area)

In a circle of radius \(r\), a chord subtends \(\theta\) at the centre. The isosceles triangle formed by two radii has: \[ \text{base } c=2r\sin(\tfrac{\theta}{2}),\qquad \text{area }=\tfrac12 r^{2}\sin\theta. \] The corresponding sector has \(A_{\text{sector}}=\tfrac12 r^{2}\theta\) and arc length \(r\theta\).

Example — \(r=10\), \(\theta=1.1\text{ rad}\) \[ c=2\cdot 10\sin(0.55)\approx 20\cdot 0.5227=10.45, \] \[ \text{Area}_{\triangle}=\tfrac12\cdot 10^{2}\sin(1.1)=50\cdot 0.8912\approx 44.56, \] \[ \text{Area}_{\text{sector}}=\tfrac12\cdot 10^{2}\cdot 1.1=55, \;\;\text{so }A_{\text{seg}}=55-44.56\approx 10.44. \] \[ \ell_{\text{arc}}=10\cdot 1.1=11,\qquad P_{\text{seg}}=\ell_{\text{arc}}+c\approx 11+10.45=21.45. \]

Key Points

  • Always use radians for \( \ell=r\theta \), \(A_{\text{sector}}=\tfrac12 r^{2}\theta\), and \(A_{\text{seg}}=\tfrac12 r^{2}(\theta-\sin\theta)\).
  • Segment perimeter = arc + chord, with \(c=2r\sin(\tfrac{\theta}{2})\).
  • Sine Rule for pairs (angle & opposite side), Cosine Rule for SAS/SSS.
  • Triangle area (non-right-angled): \(\tfrac12 ab\sin C\).<\li>
  • Right triangles: SOHCAHTOA.
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