\[
\frac{d}{dx}(\sin x)=\cos x
\]
\[
\frac{d}{dx}(\cos x)=-\sin x
\]
\[
\frac{d}{dx}(\tan x)=\sec^2 x
\]
With the chain rule:
\[
\frac{d}{dx}(\sin(f(x)))=f'(x)\cos(f(x))
\]
\[
\frac{d}{dx}(\cos(f(x)))=-f'(x)\sin(f(x))
\]
\[
\frac{d}{dx}(\tan(f(x)))=f'(x)\sec^2(f(x))
\]