The probability that a phone is not made by Company B is 0.65 (since 35% are made by Company B).

The probability that none of the n phones is made by Company B is given by \((0.65)^n\).

We want the probability that at least one phone is made by Company B to be more than 0.98, so:

\(1 - (0.65)^n > 0.98\)

\((0.65)^n < 0.02\)

Taking logarithms on both sides:

\(n \log(0.65) < \log(0.02)\)

\(n > \frac{\log(0.02)}{\log(0.65)}\)

Calculating the right-hand side gives \(n > 9.08\).

Since n must be an integer, the smallest possible value is \(n = 10\).