Feb/Mar 2019 p62 q6
3084
The results of a survey by a large supermarket show that 35% of its customers shop online.
For a random sample of n customers, the probability that at least one of them shops online is greater than 0.95. Find the least possible value of n.
Solution
\(The probability that a customer does not shop online is 0.65 (since 1 - 0.35 = 0.65).\)
The probability that none of the n customers shop online is given by:
(0.65)^n
We want the probability that at least one customer shops online to be greater than 0.95:
1 - (0.65)^n > 0.95
Rearranging gives:
(0.65)^n < 0.05
Taking logarithms on both sides:
n \log(0.65) < \log(0.05)
Solving for n gives:
\(n > \frac{\log(0.05)}{\log(0.65)} \approx 6.95\)
Therefore, the least integer value of n is 7.
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