The probability of rolling an odd number (1, 3, or 5) is given by:

\(P(\text{odd}) = \frac{1}{6} + \frac{1}{6} + \frac{2}{6} = \frac{2}{3}\)

We need to find the probability of getting at least 7 odd numbers in 8 throws, which is \(P(7) + P(8)\).

Using the binomial probability formula:

\(P(7) = \binom{8}{7} \left( \frac{2}{3} \right)^7 \left( \frac{1}{3} \right)^1 = 8 \times \left( \frac{2}{3} \right)^7 \times \frac{1}{3} = 0.156\)

\(P(8) = \binom{8}{8} \left( \frac{2}{3} \right)^8 = \left( \frac{2}{3} \right)^8 = 0.0390\)

Thus, the probability of obtaining at least 7 odd numbers is:

\(P(7 \text{ or } 8) = 0.156 + 0.0390 = 0.195\)