(b) The probability of getting a leopard in one magazine is \(p = 0.2\). We need to find the probability of getting more than two leopards in 12 magazines. This is given by:

\(1 - P(0, 1, 2) = 1 - \left( \binom{12}{0} (0.2)^0 (0.8)^{12} + \binom{12}{1} (0.2)^1 (0.8)^{11} + \binom{12}{2} (0.2)^2 (0.8)^{10} \right)\)

\(= 1 - (0.06872 + 0.20615 + 0.28347)\)

\(= 0.442\)

(c) The probability that after 5 weeks Sahim has exactly one of each animal is given by:

\((0.2)^5 \times 5!\)

\(= 0.0384 = \frac{24}{625}\)