Let the probability that a car is fitted with satellite navigation equipment be denoted by \(p = 0.76\).

The number of cars fitted with the equipment follows a binomial distribution with parameters \(n = 11\) and \(p = 0.76\).

We need to find \(P(X < 10)\), which is equivalent to \(1 - P(X \geq 10)\).

Calculate \(P(X \geq 10) = P(X = 10) + P(X = 11)\).

Using the binomial probability formula:

\(P(X = 10) = \binom{11}{10} (0.76)^{10} (0.24)^{1}\)

\(P(X = 11) = \binom{11}{11} (0.76)^{11} (0.24)^{0}\)

\(P(X = 10) = 11 \times (0.76)^{10} \times (0.24)\)

\(P(X = 11) = (0.76)^{11}\)

\(P(X \geq 10) = 11 \times (0.76)^{10} \times (0.24) + (0.76)^{11}\)

\(P(X \geq 10) = 0.219\)

Thus, \(P(X < 10) = 1 - 0.219 = 0.781\).