Let the random variable \(X\) represent the number of adults who own a car in a sample of 8. \(X\) follows a binomial distribution with parameters \(n = 8\) and \(p = 0.7\).

We need to find \(P(X < 6)\), which is equivalent to \(1 - P(X \geq 6)\).

Calculate \(P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8)\).

\(P(X = 6) = \binom{8}{6} (0.7)^6 (0.3)^2\)

\(P(X = 7) = \binom{8}{7} (0.7)^7 (0.3)^1\)

\(P(X = 8) = \binom{8}{8} (0.7)^8 (0.3)^0\)

\(P(X \geq 6) = \binom{8}{6} (0.7)^6 (0.3)^2 + \binom{8}{7} (0.7)^7 (0.3)^1 + \binom{8}{8} (0.7)^8 (0.3)^0\)

\(P(X \geq 6) = 0.55177\)

Thus, \(P(X < 6) = 1 - 0.55177 = 0.448\).