(a) The probability that a student owns a car is 0.22. The probability that all 3 students own a car is given by:

\(0.22^3 = 0.0106\)

(b) We use the binomial probability formula to find the probability that the number of students who own a car is at least 2 and at most 4 out of 16 students. The probability that a student does not own a car is 0.78.

The probability is given by:

\(P(2, 3, 4) = \binom{16}{2} (0.22)^2 (0.78)^{14} + \binom{16}{3} (0.22)^3 (0.78)^{13} + \binom{16}{4} (0.22)^4 (0.78)^{12}\)

Calculating each term:

\(\binom{16}{2} (0.22)^2 (0.78)^{14} = 0.179205\)

\(\binom{16}{3} (0.22)^3 (0.78)^{13} = 0.235877\)

\(\binom{16}{4} (0.22)^4 (0.78)^{12} = 0.216221\)

Adding these probabilities gives:

\(0.179205 + 0.235877 + 0.216221 = 0.631\)