(i) The area of parallelogram ABCD can be found using the formula for the area of a parallelogram:

Area = AB × BD × sin(ABD)

Given AB = BD = 10 cm and ABD = 0.8 radians, the area is:

Area = 10 × 10 × sin(0.8) = 100 × sin(0.8) = 71.7

(ii) The area of the complete figure ABQCDP includes the area of parallelogram ABCD and the areas of sectors APD and BQC. Each sector has a radius of 10 cm and angle 0.8 radians.

Area of one sector = \(\frac{1}{2} \times 10^2 \times 0.8 = 40\)

Total area of sectors = 2 × 40 = 80

Total area of figure = Area of parallelogram + Total area of sectors = 71.7 + 8.3 = 80

(iii) The perimeter of the complete figure ABQCDP includes the sides AB, BC, CD, DA, and the arcs APD and BQC.

Length of one arc = 10 × 0.8 = 8

Total length of arcs = 2 × 8 = 16

Perimeter = AB + BC + CD + DA + Total length of arcs = 10 + 10 + 10 + 10 + 16 = 36