Browsing as Guest. Progress, bookmarks and attempts are disabled.
Log in to track your work.
June 2008 p6 q2
2642
In country A, 30% of people who drink tea have sugar in it. In country B, 65% of people who drink tea have sugar in it. There are 3 million people in country A who drink tea and 12 million people in country B who drink tea. A person is chosen at random from these 15 million people.
Find the probability that the person chosen is from country A.
Find the probability that the person chosen does not have sugar in their tea.
Given that the person chosen does not have sugar in their tea, find the probability that the person is from country B.
Solution
(i) The probability that the person chosen is from country A is given by the ratio of the number of people in country A to the total number of people:
\(P(A) = \frac{3}{15} = 0.2\)
(ii) To find the probability that the person chosen does not have sugar in their tea, we calculate the probabilities for both countries and sum them:
In country A, 70% do not have sugar: \(0.7 \times 3 \text{ million} = 2.1 \text{ million}\)
In country B, 35% do not have sugar: \(0.35 \times 12 \text{ million} = 4.2 \text{ million}\)
Total without sugar: \(2.1 + 4.2 = 6.3 \text{ million}\)