Let:

• \(A\) be the event that a person goes abroad.
• \(C\) be the event that a person goes camping.

We need to find \(P(A \mid C)\), the probability that a person goes abroad given that they go camping.

Using the formula for conditional probability:

\(P(A \mid C) = \frac{P(A \cap C)}{P(C)}\)

Calculate \(P(A \cap C)\):

\(P(A \cap C) = P(A) \times P(C \mid A) = 0.35 \times 0.15 = 0.0525\)

Calculate \(P(C)\):

\(P(C) = P(A \cap C) + P(H \cap C)\)

Where \(H\) is the event of taking a holiday in their own country.

\(P(H \cap C) = P(H) \times P(C \mid H) = 0.65 \times 0.4 = 0.26\)

Thus,

\(P(C) = 0.0525 + 0.26 = 0.3125\)

Finally, calculate \(P(A \mid C)\):

\(P(A \mid C) = \frac{0.0525}{0.3125} = 0.168\)