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Problem 260
260
The diagram shows a sector OAB of a circle with centre O and radius r. Angle AOB is \(\theta\) radians. The point C on OA is such that BC is perpendicular to OA. The point D is on BC and the circular arc AD has centre C.
(i) Find AC in terms of r and \(\theta\).
(ii) Find the perimeter of the shaded region ABD when \(\theta = \frac{1}{3} \pi\) and r = 4, giving your answer as an exact value.
Solution
(i) To find \(AC\), note that \(AC = OA - OC\). Since \(OC = r \cos \theta\), we have:
\(AC = r - r \cos \theta\).
(ii) For the perimeter of the shaded region ABD:
1. Calculate arc AB: \(\text{arc } AB = \frac{4\pi}{3}\).