Let \(C\), \(T\), and \(M\) represent the events of having chocolate, tea, and milk, respectively. Let \(B\) represent the event of having a biscuit.

The probability that Suki does not have a biscuit, \(P(B')\), is calculated as follows:

\(P(B') = P(C \cap B') + P(T \cap B') + P(M \cap B')\)

\(P(C \cap B') = 0.45 \times (1 - 0.3) = 0.45 \times 0.7 = 0.315\)

\(P(T \cap B') = 0.35 \times (1 - 0.6) = 0.35 \times 0.4 = 0.14\)

\(P(M \cap B') = 0.2 \times 1 = 0.2\)

Thus, \(P(B') = 0.315 + 0.14 + 0.2 = 0.655\)

We need to find \(P(T | B')\), the probability that Suki has tea given that she does not have a biscuit:

\(P(T | B') = \frac{P(T \cap B')}{P(B')} = \frac{0.14}{0.655}\)

Calculating this gives:

\(P(T | B') = \frac{0.14}{0.655} \approx 0.214\)

Therefore, the probability that Suki has tea given that she does not have a biscuit is \(0.214\) or \(\frac{28}{131}\).