(i) Total number of selections = \(\binom{12}{7} = 792\).

Selections with the boy included = \(\binom{11}{6} = 462\).

Probability = \(\frac{462}{792} = \frac{7}{12}\).

(ii) Method 1: Scenarios are:

• 2G + 5B: \(\binom{4}{2} \times \binom{8}{5} = 336\)
• 3G + 4B: \(\binom{4}{3} \times \binom{8}{4} = 280\)
• 4G + 3B: \(\binom{4}{4} \times \binom{8}{3} = 56\)

\(Total = 672.\)

Probability = \(\frac{672}{792} = \frac{28}{33}\).