Each die has 4 faces, so there are a total of 16 possible outcomes when two dice are thrown together.

To find the probability of the sum being 7 or more, we consider the following outcomes:

• Sum of 7: Possible outcomes are (3,4) and (4,3), giving a probability of \(\frac{2}{16}\).
• Sum of 8: The only possible outcome is (4,4), giving a probability of \(\frac{1}{16}\).

Thus, the probability of the sum being 7 or more is:

\(P(7 \text{ or more}) = \frac{2}{16} + \frac{1}{16} = \frac{3}{16}\)

The expected number of occasions when the sum is 7 or more in 200 throws is:

\(200 \times \frac{3}{16} = 37.5\)