Let the houses with numbers greater than 14 be 16, 18, 20, 22, and 24. There are 5 such houses.

We need to find the probability that at least 2 newspapers are delivered to these 5 houses.

This can be calculated as \(P(2) + P(3)\) or \(1 - P(0, 1)\).

Calculate \(P(2)\):

\(P(2) = \frac{5}{12} \times \frac{4}{11} \times \frac{7}{10} \times \binom{3}{2}\)

Calculate \(P(3)\):

\(P(3) = \frac{5}{12} \times \frac{4}{11} \times \frac{3}{10}\)

Thus, \(P(\text{at least 2}) = P(2) + P(3) = \frac{4}{11}\).

Alternatively, using combinations:

\(\frac{\binom{5}{3} + \binom{5}{2} \times \binom{7}{1}}{\binom{12}{3}} = \frac{4}{11}\).