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Problem 250
250
The diagram shows triangle ABC in which AB is perpendicular to BC. The length of AB is 4 cm and angle CAB is \(\alpha\) radians. The arc DE with centre A and radius 2 cm meets AC at D and AB at E. Find, in terms of \(\alpha\),
(i) the area of the shaded region,
Solution
To find the area of the shaded region, we need to calculate the area of triangle ABC and subtract the area of sector ADE.
The area of triangle ABC is given by:
\(\text{Area of } \triangle ABC = \frac{1}{2} \times AB \times BC = \frac{1}{2} \times 4 \times 4 \tan \alpha = 8 \tan \alpha\)