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Problem 239
239
The diagram shows a metal plate OABCDEF consisting of 3 sectors, each with centre O. The radius of sector COD is 2r and angle COD is θ radians. The radius of each of the sectors BOA and FOE is r, and AOED and CBOF are straight lines.
(i) Show that the area of the metal plate is r^2(π + θ).
(ii) Show that the perimeter of the metal plate is independent of θ.
Solution
(i) The area of sector OCD is given by \(\frac{1}{2} (2r)^2 \theta = 2r^2 \theta\).
The area of sectors OAB and OEF is \(2 \times \frac{1}{2} r^2 (\pi - \theta) = r^2 (\pi - \theta)\).
Thus, the total area of the metal plate is \(2r^2 \theta + r^2 (\pi - \theta) = r^2 (\pi + \theta)\).
(ii) The arc length CD is \(2r \theta\).
The arc lengths AB and EF are \(2 \times r (\pi - \theta) = 2r (\pi - \theta)\).
The straight edges AO, OE, BO, and OF sum to \(4r\).
Thus, the total perimeter is \(2r \theta + 2r (\pi - \theta) + 4r = 2\pi r + 4r\), which is independent of \(\theta\).