(i) To find the perimeter of the shaded region, we need to calculate the lengths of CD, BD, and the arc CB.

The length of CD is given by \(CD = r \cos \theta\).

The length of BD is given by \(BD = r - r \sin \theta\).

The length of the arc CB is given by \(r \left( \frac{1}{2} \pi - \theta \right)\).

Thus, the perimeter \(P\) is:

\(P = r \cos \theta + r - r \sin \theta + r \left( \frac{1}{2} \pi - \theta \right)\)

(ii) To find the area of the shaded region when r = 5 cm and θ = 0.6, we calculate the area of the sector and subtract the areas of triangle AOC and sector COD.

The area of sector AOB is \(\frac{1}{2} \times 5^2 \times \left( \frac{1}{2} \pi - 0.6 \right) = 12.135\).

The area of triangle AOC is \(\frac{1}{2} \times 5 \times \cos 0.6 \times 5 \times \sin 0.6 = 5.825\).

The area of the shaded region is:

\(12.135 - 5.825 = 6.31\)