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Problem 234
234
In the diagram, OCA and ODB are radii of a circle with centre O and radius 2r cm. Angle AOB = α radians. CD and AB are arcs of circles with centre O and radii r cm and 2r cm respectively. The perimeter of the shaded region ABDC is 4.4r cm.
(i) Find the value of α.
(ii) It is given that the area of the shaded region is 30 cm². Find the value of r.
Solution
(i) The perimeter of the shaded region ABDC is given by the sum of the lengths of arcs AB and CD, and the radii OA and OB. The length of arc AB is \(2r\alpha\) and the length of arc CD is \(r\alpha\). Therefore, the perimeter is:
\(2r\alpha + r\alpha + 2r = 4.4r\)
Simplifying, we get:
\(3r\alpha + 2r = 4.4r\)
\(3r\alpha = 2.4r\)
\(\alpha = 0.8\)
(ii) The area of the shaded region is the difference between the area of sector OAB and sector OCD. The area of sector OAB is \(\frac{1}{2}(2r)^2\alpha\) and the area of sector OCD is \(\frac{1}{2}r^2\alpha\). Therefore, the area of the shaded region is: