(a) Each arc has radius \(2\) and angle \(\pi/3\). Hence \(P=3(2\pi/3)=\boxed{2\pi\text{ cm}}\).

(b) The area is the equilateral triangle plus three circular segments. The triangle area is \(\sqrt3\), and each segment has area \(\tfrac12(2^2)(\pi/3)-\sqrt3\). Thus \(A=\sqrt3+3(2\pi/3-\sqrt3)=\boxed{2\pi-2\sqrt3\text{ cm}^2}\).