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Problem 196
196
The diagram shows a triangle ABC, in which angle ABC = 90^ ext{o} and AB = 4 ext{ cm}. The sector ABD is part of a circle with centre A. The area of the sector is 10 ext{ cm}^2.
(a) Find angle BAD in radians.
(b) Find the perimeter of the shaded region.
Solution
(a) To find angle BAD, use the formula for the area of a sector: \(\frac{1}{2} \times r^2 \times \theta = 10\). Here, \(r = 4\) cm and \(\theta\) is the angle in radians.
\(\frac{1}{2} \times 4^2 \times \theta = 10\)
\(8 \theta = 10\)
\(\theta = \frac{10}{8} = 1.25\) radians
(b) To find the perimeter of the shaded region, calculate the arc length BD and the lengths BC and CD.
Arc BD = \(4 \times 1.25 = 5\) cm
Using \(BC = 4 \tan(1.25)\), calculate \(BC\).
\(BC \approx 12.04\) cm
Using \(CD = \frac{4}{\cos(1.25)} - 4\), calculate \(CD\).
\(CD \approx 8.69\) cm
Perimeter = Arc BD + BC + CD = \(5 + 12.04 + 8.69 = 25.7\) cm