Many real-life measurements (such as heights, exam scores and measurement errors) follow a normal distribution.
If a variable \(X\) follows a normal distribution:
\( X \sim N(\mu, \sigma^2) \)
The distribution is:
To find probabilities we convert values into a standard normal variable:
::contentReference[oaicite:0]{index=0}Where:
After calculating \(Z\), we use normal distribution tables.
The weights of apples in a farm are normally distributed with mean \( \mu = 150 \) g and standard deviation \( \sigma = 20 \) g.
Find \(P(X > 180)\).
Step 1: Standardise
\[ Z = \frac{180 - 150}{20} \] \[ Z = 1.5 \]Step 2: Use tables
\[ P(Z < 1.5) = 0.9332 \]Therefore:
\[ P(Z > 1.5) = 1 - 0.9332 \]Exam scores follow \(N(70,10^2)\).
Find the mark exceeded by the top 10% of students.
From tables:
\[ P(Z > z) = 0.10 \] \[ z = 1.28 \]Now convert back to \(X\):
\[ X = \mu + z\sigma \] \[ X = 70 + (1.28)(10) \]The top 10% scored about 83 marks or more.