Partial fractions rewrite a complicated rational expression into simpler fractions that can be integrated or simplified easily.
A rational expression of the form \(\dfrac{P(x)}{Q(x)}\) can be rewritten as a sum of simpler fractions, provided the degree of the numerator is less than the degree of the denominator.
Example factorizations:
Example 1: \(\displaystyle \frac{5x+3}{x(x+2)}\)
Assume \[ \frac{5x+3}{x(x+2)} = \frac{A}{x} + \frac{B}{x+2} \] Multiply by \(x(x+2)\): \[ 5x + 3 = A(x+2) + Bx \] Expand: \[ 5x + 3 = (A + B)x + 2A \] Compare coefficients: \[ A + B = 5,\qquad 2A = 3 \] So \(A = \tfrac{3}{2}\), \(B = \tfrac{7}{2}\).
Example 2 (quadratic denominator): \(\displaystyle \frac{2x+7}{(x+1)(x^2+4)}\)
Assume \[ \frac{2x+7}{(x+1)(x^2+4)} = \frac{A}{x+1} + \frac{Bx + C}{x^2 + 4} \] Multiply by denominator: \[ 2x + 7 = A(x^2 + 4) + (Bx + C)(x+1) \] Expand and compare coefficients to solve for \(A, B, C\).
Example 3 (Repeated linear): \(\displaystyle \frac{4}{x^2(x+3)}\)
Form: \[ \frac{4}{x^2(x+3)} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x+3} \] Multiply by \(x^2(x+3)\), expand, solve A, B, C.
Example 4 (Improper fraction): \(\displaystyle \frac{2x^2 + 3x + 1}{x+2}\)
First divide: \[ \frac{2x^2 + 3x + 1}{x+2} = 2x - 1 + \frac{3}{x+2} \] Now it's ready for integration.
Example 5 (Integration): \(\displaystyle \int \frac{6x+5}{x^2 - x} \, dx\)
Factor denominator: \[ x^2 - x = x(x-1) \] Write: \[ \frac{6x + 5}{x(x-1)} = \frac{A}{x} + \frac{B}{x-1} \] Solve for \(A\), \(B\).
Then integrate: \[ \int \frac{A}{x}\,dx = A\ln|x|,\qquad \int \frac{B}{x-1}\,dx = B\ln|x-1| \]
Once split into partial fractions, you typically use these: