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9231 FP2 · Notes & worked examples

Arc length and surface areas · Short practice

Check a final answer, then explain the reasoning on paper. Guest progress stays in this browser; an account saves future checks without overwriting your first result.

Recall

Arc length and surface area — objective 1

Maths4U Original · Short practice

On \(0\le x\le 3\), the curve is \(\displaystyle y= \frac{2}{3}(x+ 12)^{\frac{3}{2}}\).

Find its arc length.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

Fresh review variant

Arc length and surface area — objective 1

Maths4U Original · Short practice

On \(0\le x\le 1\), the curve is \(\displaystyle y= \frac{2}{3}(x+ 13)^{\frac{3}{2}}\).

Find its arc length.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

Method

Arc length and surface area — objective 2

Maths4U Original · Short practice

On \(0\le x\le 1\), the curve is \(\displaystyle y= \frac{2}{3}(x+ 13)^{\frac{3}{2}}\).

Find \(\displaystyle \frac{S}{\pi}\) for the curved surface produced by revolution about the x-axis.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

Fresh review variant

Arc length and surface area — objective 2

Maths4U Original · Short practice

On \(0\le x\le 2\), the curve is \(\displaystyle y= \frac{2}{3}(x+ 14)^{\frac{3}{2}}\).

Find \(\displaystyle \frac{S}{\pi}\) for the curved surface produced by revolution about the x-axis.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

Apply

Arc length and surface area — objective 3

Maths4U Original · Short practice

On \(0\le x\le 2\), the curve is \(\displaystyle y= \frac{2}{3}(x+ 14)^{\frac{3}{2}}\).

Find \(\displaystyle \frac{V}{\pi}\) for the solid formed from the region under the curve.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

Fresh review variant

Arc length and surface area — objective 3

Maths4U Original · Short practice

On \(0\le x\le 3\), the curve is \(\displaystyle y= \frac{2}{3}(x+ 15)^{\frac{3}{2}}\).

Find \(\displaystyle \frac{V}{\pi}\) for the solid formed from the region under the curve.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

Check understanding

Arc length and surface area — objective 4

Maths4U Original · Short practice

On \(0\le x\le 3\), the curve is \(\displaystyle y= \frac{2}{3}(x+ 15)^{\frac{3}{2}}\).

Find the gradient at the right endpoint.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

Fresh review variant

Arc length and surface area — objective 4

Maths4U Original · Short practice

On \(0\le x\le 1\), the curve is \(\displaystyle y= \frac{2}{3}(x+ 16)^{\frac{3}{2}}\).

Find the gradient at the right endpoint.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

Try written exam-style problems →