Maths4U
Menu

Maths4U Original · Learn, check, explain

Braking, stopping time and stopping distance — 9709 P4

Use a negative acceleration for a vehicle still moving forwards.

Syllabus 4.2

Notes and key methods

For braking from forward speed u with constant deceleration magnitude b, take \(\displaystyle a=-b\). At the first stop, \(\displaystyle v=0\). The stopping time and braking distance follow from the relations below.

The model ends at the first stop unless continued motion is explicitly specified. Continuing \(\displaystyle a=-b\) beyond that time would predict reversal, not continued braking to rest. With a reaction interval, add the distance at the unchanged speed before braking begins.

\(\displaystyle t_{\mathrm{stop}}= \frac{u}{b}, \quad s_{\mathrm{brake}}= \frac{u^{2}}{2b}\)

Check the conditions

Three worked examples

Example 1 · Braking, stopping time and stopping distance

A vehicle travels forwards at \(\displaystyle \frac{13m}{s}\). After a reaction interval of \(\displaystyle \frac{1}{2}\) s at unchanged speed, it brakes with constant deceleration magnitude \(\displaystyle \frac{2m}{s^{2}}\) until its first stop. Ignore all other effects.

  1. Find the braking time in s, excluding reaction time.
  2. Find the braking distance in m, excluding reaction distance.
  3. Find the reaction distance in m.
  4. Find the full stopping distance from the start of the reaction interval, in m.
Show the reasoning

(a)

Apply the zero final velocity to the braking stage only.

Set 0=u−bt to obtain \(\displaystyle \frac{13}{2}\) s.

Answer: \(\displaystyle \frac{13}{2}\).

(b)

Use the signed braking acceleration in the time-free equation.

Using 0=u²−2bD gives \(\displaystyle \frac{169}{4}\) m.

Answer: \(\displaystyle \frac{169}{4}\).

(c)

Use constant speed during the stated reaction interval.

Unchanged speed times reaction time gives \(\displaystyle \frac{13}{2}\) m.

Answer: \(\displaystyle \frac{13}{2}\).

(d)

Combine the two stage distances without including a post-stop reversal.

Add the reaction and braking distances to obtain \(\displaystyle \frac{195}{4}\) m.

Answer: \(\displaystyle \frac{195}{4}\).

Example 2 · Braking, stopping time and stopping distance

A vehicle travels forwards at \(\displaystyle \frac{14m}{s}\). After a reaction interval of \(1\) s at unchanged speed, it brakes with constant deceleration magnitude \(\displaystyle \frac{3m}{s^{2}}\) until its first stop. Ignore all other effects.

  1. Find the braking time in s, excluding reaction time.
  2. Find the braking distance in m, excluding reaction distance.
  3. Find the reaction distance in m.
  4. Find the full stopping distance from the start of the reaction interval, in m.
Show the reasoning

(a)

Apply the zero final velocity to the braking stage only.

Set 0=u−bt to obtain \(\displaystyle \frac{14}{3}\) s.

Answer: \(\displaystyle \frac{14}{3}\).

(b)

Use the signed braking acceleration in the time-free equation.

Using 0=u²−2bD gives \(\displaystyle \frac{98}{3}\) m.

Answer: \(\displaystyle \frac{98}{3}\).

(c)

Use constant speed during the stated reaction interval.

Unchanged speed times reaction time gives \(14\) m.

Answer: \(14\).

(d)

Combine the two stage distances without including a post-stop reversal.

Add the reaction and braking distances to obtain \(\displaystyle \frac{140}{3}\) m.

Answer: \(\displaystyle \frac{140}{3}\).

Example 3 · Braking, stopping time and stopping distance

A vehicle travels forwards at \(\displaystyle \frac{15m}{s}\). After a reaction interval of \(\displaystyle \frac{3}{2}\) s at unchanged speed, it brakes with constant deceleration magnitude \(\displaystyle \frac{4m}{s^{2}}\) until its first stop. Ignore all other effects.

  1. Find the braking time in s, excluding reaction time.
  2. Find the braking distance in m, excluding reaction distance.
  3. Find the reaction distance in m.
  4. Find the full stopping distance from the start of the reaction interval, in m.
Show the reasoning

(a)

Apply the zero final velocity to the braking stage only.

Set 0=u−bt to obtain \(\displaystyle \frac{15}{4}\) s.

Answer: \(\displaystyle \frac{15}{4}\).

(b)

Use the signed braking acceleration in the time-free equation.

Using 0=u²−2bD gives \(\displaystyle \frac{225}{8}\) m.

Answer: \(\displaystyle \frac{225}{8}\).

(c)

Use constant speed during the stated reaction interval.

Unchanged speed times reaction time gives \(\displaystyle \frac{45}{2}\) m.

Answer: \(\displaystyle \frac{45}{2}\).

(d)

Combine the two stage distances without including a post-stop reversal.

Add the reaction and braking distances to obtain \(\displaystyle \frac{405}{8}\) m.

Answer: \(\displaystyle \frac{405}{8}\).

Common mistakes

Practise with answer checking

Original exam-style problems

Write complete solutions before opening the worked solution. The marking guidance rewards reasoning as well as answers.

Examination practice · 2020–2026

Apply the method to recent source-labelled questions from this chapter.

Browse recent examination questions · All topic resources and the full bank

Next skill: Two particles meeting on a straight line →