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Complex numbers — chapter review — 9231 FP2

Separate modulus from argument when taking powers. Enumerate distinct roots by equally spaced arguments. Use a finite geometric formula and then take real or imaginary parts.

Notes and key methods

For \(z=r(\cos\theta+i\sin\theta)\), de Moivre gives \(z^n=r^n[\cos(n\theta)+i\sin(n\theta)]\). Arguments are determined modulo 2π, so a principal argument may need reducing to the specified interval.

The real and imaginary parts are \(\displaystyle r^{n}\cos (n\theta )\) and \(\displaystyle r^{n}\sin (n\theta )\). The modulus is nonnegative; a negative real part does not make the modulus negative.

The m roots of \(z^m=R^me^{i\phi}\), with R>0, are \(\displaystyle R\exp [\frac{i(\phi + 2k\pi )}{m}]\), \(\displaystyle k=0\),…,m−1. Their arguments differ by \(\displaystyle \frac{2\pi }{m}\) and the roots form a regular polygon on a circle.

For roots of unity take \(\displaystyle R=1\) and \(\displaystyle \phi =0\). Geometric sums provide identities for sums of roots and related trigonometric series; list exactly m distinct values.

For \(\displaystyle z\ne 1\), \(\displaystyle \sum_{k= 0}^{n- 1} z^{k}= \frac{z^{n}- 1}{z- 1}\). Write z in polar form, then take real or imaginary parts to obtain corresponding weighted cosine or sine sums.

The initial power matters: a sum starting at \(\displaystyle k=1\) is z times the sum starting at \(\displaystyle k=0\). For \(\displaystyle z=1\) use n directly, rather than dividing by zero in the geometric formula.

Check the conditions

Three worked examples

Example 1 · de Moivre and complex powers

\(\displaystyle z= 4[\cos (\frac{\pi }{5})+ i\sin (\frac{\pi }{5})]\), with \(\displaystyle n=5\).

  1. Find the modulus of \(\displaystyle z^{n}\).
  2. Find \(\displaystyle \operatorname{Re}(z^{n})\).
  3. Find \(\displaystyle \operatorname{Im}(z^{n})\).
  4. Find \(\displaystyle |z^{n}|^{2}\).
Show the reasoning

(a)

\(r^n=1024\)

Answer: \(1024\).

(b)

\(\displaystyle 4^{5}\cos (\frac{5\pi }{5})= - 1024\)

Answer: \(-1024\).

(c)

\(\displaystyle 4^{5}\sin (\frac{5\pi }{5})= 1.25403832232689\times 10^{- 13}\)

Answer: \(1.25403832232689\times10^{-13}\).

(d)

\(r^{2n}=1048576\)

Answer: \(1048576\).

Example 2 · Complex roots and roots of unity

Find the roots of \(\displaystyle z^{6}= 5^{6}e^{\frac{i\pi }{2}}\). For angle answers use radians and arguments in [0,2π).

  1. Find the common modulus of the roots.
  2. Find the smallest nonnegative root argument.
  3. Find the angular spacing between successive roots.
  4. Find the real part of the root with smallest nonnegative argument.
Show the reasoning

(a)

\(\displaystyle |z|= (5^{6})^{\frac{1}{6}}= 5\)

Answer: \(5\).

(b)

\(\displaystyle \theta_{0}= \frac{\pi }{2\cdot 6}\)

Answer: \(0.261799387799149\).

(c)

\(\displaystyle \frac{2\pi }{6}\)

Answer: \(1.0471975511966\).

(d)

\(\displaystyle 5\cos (\frac{\pi }{12})= 4.82962913144534\)

Answer: \(4.82962913144534\).

Example 3 · Complex geometric sums

\(\displaystyle z= 3e^{\frac{i\pi }{7}}\) and \(S=\sum_{k=0}^{2}z^k\).

  1. Find Re(S).
  2. Find Im(S).
  3. Find \(\displaystyle |S|^{2}\).
  4. Find the real part of the sum from \(\displaystyle k=1\) to \(\displaystyle k=3\).
Show the reasoning

(a)

\(\displaystyle S= \frac{z^{n}- 1}{z- 1}\) gives \(\Re(S)=9.31431482043586\).

Answer: \(9.31431482043586\).

(b)

\(\Im(S)=8.33813455956494\)

Answer: \(8.33813455956494\).

(c)

\(|S|^2=\Re(S)^2+\Im(S)^2=156.280948507602\)

Answer: \(156.280948507602\).

(d)

\(\sum_{k=1}^{n}z^k=zS\); real part \(14.3223800372564\).

Answer: \(14.3223800372564\).

Common mistakes

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Original exam-style problems

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