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Integration — chapter review — 9231 FP2

Choose substitution, inverse forms, partial fractions or integration by parts. Set up geometric integrals with the correct element of length. Express a rectangular sum using standard sums and pass to its limit.

Notes and key methods

A substitution must transform the whole integrand, differential and limits. Recognise \(\int x/(x^2+a^2)\,dx=\frac12\ln(x^2+a^2)+C\), and \(\int dx/\sqrt{x^2+a^2}=\operatorname{arsinh}(x/a)+C\) for a>0.

Use integration by parts \(\int u\,dv=uv-\int v\,du\) when differentiating one factor simplifies it. A proper rational function may instead be decomposed into partial fractions. Check an antiderivative by differentiation.

For a smooth curve y=f(x), arc length is \(L=\int_a^b\sqrt{1+(dy/dx)^2}\,dx\). For revolution about the x-axis with y≥0, curved surface area is \(S=2\pi\int_a^b y\sqrt{1+(dy/dx)^2}\,dx\).

Volume uses \(\pi\int y^2dx\), a different geometric quantity. When working parametrically, replace the arc element by √[(dx/dt)²+(dy/dt)²]dt.

With n equal subintervals of width h=(b−a)/n, a right-endpoint sum is \(h\sum_{r=1}^n f(a+rh)\). For a continuous function this tends to the definite integral as n increases.

If f is increasing and nonnegative, the left sum is a lower bound and the right sum is an upper bound. Derive the finite expression before taking a limit, and keep the factor h outside the sum.

Check the conditions

Three worked examples

Example 1 · Advanced integration techniques

Evaluate the following independent definite integrals on [0,1]. Show a suitable method.

  1. Evaluate \(\int_0^1 x/(x^2+9)\,dx\).
  2. Evaluate \(\int_0^1 (x^2+9)^{-1/2}\,dx\).
  3. Evaluate \(\int_0^1 xe^{2x}\,dx\).
  4. Evaluate \(\int_0^1 1/[(x+3)(x+4)]\,dx\).
Show the reasoning

(a)

\(\frac12[\ln(x^2+9)]_0^1=0.0526802578289132\)

Answer: \(0.0526802578289132\).

(b)

\([\operatorname{arsinh}(x/3)]_0^1=0.327450150237258\)

Answer: \(0.327450150237258\).

(c)

\([e^{2x}(x/2-1/4)]_0^1=2.09726402473266\)

Answer: \(2.09726402473266\).

(d)

\([\ln(x+3)-\ln(x+4)]_0^1=0.0645385211375712\)

Answer: \(0.0645385211375712\).

Example 2 · Arc length and surface area

On \(0\le x\le 3\), the curve is \(y=\frac23(x+3)^{3/2}\).

  1. Find its arc length.
  2. Find S/π for the curved surface produced by revolution about the x-axis.
  3. Find V/π for the solid formed from the region under the curve.
  4. Find the gradient at the right endpoint.
Show the reasoning

(a)

\(\int_0^3\sqrt{x+4}\,dx=\frac23[(x+4)^{3/2}]_0^3=7.01350611830142\)

Answer: \(7.01350611830142\).

(b)

\(S/\pi=2\int_0^3\frac23(x+3)^{3/2}\sqrt{x+4}\,dx=92.5503563074016\)

Answer: \(92.5503563074016\).

(c)

\(V/\pi=\int_0^3\frac49(x+3)^3\,dx=135\)

Answer: \(135\).

(d)

\(y'(3)=\sqrt{6}\)

Answer: \(2.44948974278318\).

Example 3 · Limits of areas and sums

Consider the area under \(y=x^2+4x\) on \(0\le x\le 2\). For the finite sums use 6 equal subintervals.

  1. Find the exact integral.
  2. Find the right-endpoint rectangle sum.
  3. Find the left-endpoint rectangle sum.
  4. Find the difference between right and left sums.
Show the reasoning

(a)

\([x^3/3+4x^2/2]_0^2=\frac{32}{3}\)

Answer: \(\frac{32}{3}\).

(b)

\(h\sum_{r=1}^n[(rh)^2+a(rh)]=\frac{343}{27}\)

Answer: \(\frac{343}{27}\).

(c)

\(h\sum_{r=0}^{n-1}[(rh)^2+a(rh)]=\frac{235}{27}\)

Answer: \(\frac{235}{27}\).

(d)

\(h[f(b)-f(0)]=4\)

Answer: \(4\).

Common mistakes

Practise with answer checking

Original exam-style problems

Write complete solutions before opening the worked solution. The marking guidance rewards reasoning as well as answers.

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