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Maclaurin series — 9231 FP2

Recover polynomial coefficients from derivatives at zero.

Notes and key methods

A Maclaurin expansion starts \(f(x)=f(0)+f'(0)x+f''(0)x^2/2!+f^{(3)}(0)x^3/3!+\cdots\). Each coefficient includes its factorial denominator.

For a product, multiply truncated series while collecting every contribution to a given power. A truncated expression is an approximation away from zero; state the retained order rather than treating it as an exact identity.

Check the conditions

Three worked examples

Example 1 · Maclaurin expansions

Let \(f(x)=e^{4 x} \cos{\left(x \right)}\). Write \(f(x)=1+Ax+Bx^2+Cx^3+O(x^4)\).

  1. Find A.
  2. Find B.
  3. Find C.
  4. Use the cubic polynomial to approximate f(\frac{1}{50}).
Show the reasoning

(a)

\(A=f'(0)=4\)

Answer: \(4\).

(b)

\(B=f''(0)/2!=\frac{15}{2}\)

Answer: \(\frac{15}{2}\).

(c)

\(C=f^{(3)}(0)/3!=\frac{26}{3}\)

Answer: \(\frac{26}{3}\).

(d)

\(\frac{26 x^{3}}{3} + \frac{15 x^{2}}{2} + 4 x + 1\quad\text{at }x=\frac{1}{50}\quad=\frac{406151}{375000}\)

Answer: \(\frac{406151}{375000}\).

Example 2 · Maclaurin expansions

Let \(f(x)=e^{x} \cos{\left(2 x \right)}\). Write \(f(x)=1+Ax+Bx^2+Cx^3+O(x^4)\).

  1. Find A.
  2. Find B.
  3. Find C.
  4. Use the cubic polynomial to approximate f(\frac{1}{25}).
Show the reasoning

(a)

\(A=f'(0)=1\)

Answer: \(1\).

(b)

\(B=f''(0)/2!=- \frac{3}{2}\)

Answer: \(- \frac{3}{2}\).

(c)

\(C=f^{(3)}(0)/3!=- \frac{11}{6}\)

Answer: \(- \frac{11}{6}\).

(d)

\(- \frac{11 x^{3}}{6} - \frac{3 x^{2}}{2} + x + 1\quad\text{at }x=\frac{1}{25}\quad=\frac{48632}{46875}\)

Answer: \(\frac{48632}{46875}\).

Example 3 · Maclaurin expansions

Let \(f(x)=e^{2 x} \cos{\left(3 x \right)}\). Write \(f(x)=1+Ax+Bx^2+Cx^3+O(x^4)\).

  1. Find A.
  2. Find B.
  3. Find C.
  4. Use the cubic polynomial to approximate f(\frac{3}{50}).
Show the reasoning

(a)

\(A=f'(0)=2\)

Answer: \(2\).

(b)

\(B=f''(0)/2!=- \frac{5}{2}\)

Answer: \(- \frac{5}{2}\).

(c)

\(C=f^{(3)}(0)/3!=- \frac{23}{3}\)

Answer: \(- \frac{23}{3}\).

(d)

\(- \frac{23 x^{3}}{3} - \frac{5 x^{2}}{2} + 2 x + 1\quad\text{at }x=\frac{3}{50}\quad=\frac{34667}{31250}\)

Answer: \(\frac{34667}{31250}\).

Common mistakes

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Original exam-style problems

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