Study guides › 0606 › Calculus - Differentiation 1
Maths4U Original · Learn, check, explain
The product rule — 0606
Differentiate a product and check by expansion.
1. Understand 2. See examples 3. Check answers 4. Explain your working
Notes and key methods For \(\displaystyle y=uv, y'=u'v+uv'\). Both terms are needed, even when one factor is linear. Combining this with the chain rule handles products such as \(\displaystyle (ax+b)(x+c)^{n}\).
Differentiate the first derivative carefully to find y″; an independent expansion provides a useful algebraic check.
Check the conditions Use u′v+uv′, retaining both terms. Apply the chain rule inside either factor.
Three worked examples Example 1 · The product rule for algebraic functions Let \(f(x)=\left(x + 3\right)^{4} \left(4 x + 4\right)\), with real x.
Differentiate the given function, showing the rule used. Find the second derivative. Find the equation of the tangent at \(x=0\). Find the leading coefficient of f′(x). Show the reasoning (a) \(4 \left(x + 3\right)^{4} + 4 \left(x + 3\right)^{3} \left(4 x + 4\right)\) follows by differentiating each factor or inner function as required.
Answer: \(f'(x) = 4 \left(x + 3\right)^{4} + 4 \left(x + 3\right)^{3} \left(4 x + 4\right)\)
(b) Differentiate the complete first derivative and simplify. \(16 \left(x + 3\right)^{2} \left(5 x + 9\right)\)
Answer: \(16 \left(x + 3\right)^{2} \left(5 x + 9\right)\)
(c) The point has height \(324\) and gradient \(756\). Use \(y-y_0=m(x-x_0)\) to obtain \(y=756 x + 324\).
Answer: \(y=756 x + 324\)
(d) Differentiate the leading term \(\displaystyle ax^{n+1}\).
\(20\)
Answer: \(20\).
Example 2 · The product rule for algebraic functions Let \(f(x)=\left(x + 1\right)^{2} \left(5 x + 5\right)\), with real x.
Differentiate the given function, showing the rule used. Find the second derivative. Find the equation of the tangent at \(x=0\). Find the leading coefficient of f′(x). Show the reasoning (a) \(5 \left(x + 1\right)^{2} + \left(2 x + 2\right) \left(5 x + 5\right)\) follows by differentiating each factor or inner function as required.
Answer: \(f'(x) = 5 \left(x + 1\right)^{2} + \left(2 x + 2\right) \left(5 x + 5\right)\)
(b) Differentiate the complete first derivative and simplify. \(30 \left(x + 1\right)\)
Answer: \(30 \left(x + 1\right)\)
(c) The point has height \(5\) and gradient \(15\). Use \(y-y_0=m(x-x_0)\) to obtain \(y=15 x + 5\).
Answer: \(y=15 x + 5\)
(d) Differentiate the leading term \(\displaystyle ax^{n+1}\).
\(15\)
Answer: \(15\).
Example 3 · The product rule for algebraic functions Let \(f(x)=\left(x + 2\right)^{3} \left(2 x + 6\right)\), with real x.
Differentiate the given function, showing the rule used. Find the second derivative. Find the equation of the tangent at \(x=0\). Find the leading coefficient of f′(x). Show the reasoning (a) \(2 \left(x + 2\right)^{3} + 3 \left(x + 2\right)^{2} \left(2 x + 6\right)\) follows by differentiating each factor or inner function as required.
Answer: \(f'(x) = 2 \left(x + 2\right)^{3} + 3 \left(x + 2\right)^{2} \left(2 x + 6\right)\)
(b) Differentiate the complete first derivative and simplify. \(12 \left(x + 2\right) \left(2 x + 5\right)\)
Answer: \(12 \left(x + 2\right) \left(2 x + 5\right)\)
(c) The point has height \(48\) and gradient \(88\). Use \(y-y_0=m(x-x_0)\) to obtain \(y=88 x + 48\).
Answer: \(y=88 x + 48\)
(d) Differentiate the leading term \(\displaystyle ax^{n+1}\).
\(8\)
Answer: \(8\).
Common mistakes The derivative of a product is not the product of the derivatives. Do not lose a term when differentiating twice. Practise with answer checking
Original exam-style problems Write complete solutions before opening the worked solution. The marking guidance rewards reasoning as well as answers.
Next skill: The quotient rule →
About these materials Prepared independently from learning objectives with AI assistance for Maths4U. Mathematical checks accompany the authored models; independent teacher review is pending. Maths4U marking guidance is not an official examination-board mark scheme. Existing questions keep their original sources and results.