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Completing the square and quadratic turning points — 0580

Expose a quadratic vertex by completing the whole square.

Extended · Syllabus E2.2, E2.5, E2.11

Notes and key methods

Factor out the coefficient of \(\displaystyle x^{2}\) before completing the square inside the bracket. Use \(\displaystyle x^{2}\)+px=\(\displaystyle (x+ \frac{p}{2})^{2}- (\frac{p}{2})^{2}\), and multiply every correction back by the original coefficient.

The form \(\displaystyle a(x-h)^{2}+k\) has vertex (h,k). When a>0 its minimum is k; when a<0 it has a maximum. To solve a related equation, isolate the square and consider both real signs, checking whether the squared value can be nonnegative.

Check the conditions

Three worked examples

Example 1 · Completing the square and quadratic turning points

For real x, \(f(x)=2 x^{2} - 8 x + 14\).

Diagram for this worked example
Read the description and labels. Geometric sketches are schematic unless coordinate scales are shown.
  1. Write f in completed-square form and state the vertex.
  2. State the range of f and justify it.
  3. Solve \(f(x)=24\).
  4. Find the y-intercept of the graph.
Show the reasoning

(a)

\(f(x)=2 \left(x - 2\right)^{2} + 6\) expands to the given expression. The square vanishes at \(\displaystyle x=2\).

Answer: \(2 \left(x - 2\right)^{2} + 6\); vertex \(\left( 2, \ 6\right)\)

(b)

The square is nonnegative and its coefficient 2 is positive. Equality is attained at \(\displaystyle x=2\).

Answer: \(f(x)\ge 6\)

(c)

\((x-2)^2=9\) gives both signs: \(\displaystyle x=2\pm 3\).

Answer: \(\left\{-1, 5\right\}\)

(d)

Complete the square, then use the vertex form and its positive leading coefficient.

\(14\)

Answer: \(14\).

Example 2 · Completing the square and quadratic turning points

For real x, \(f(x)=3 x^{2} - 18 x + 34\).

Diagram for this worked example
Read the description and labels. Geometric sketches are schematic unless coordinate scales are shown.
  1. Write f in completed-square form and state the vertex.
  2. State the range of f and justify it.
  3. Solve \(f(x)=55\).
  4. Find the y-intercept of the graph.
Show the reasoning

(a)

\(f(x)=3 \left(x - 3\right)^{2} + 7\) expands to the given expression. The square vanishes at \(\displaystyle x=3\).

Answer: \(3 \left(x - 3\right)^{2} + 7\); vertex \(\left( 3, \ 7\right)\)

(b)

The square is nonnegative and its coefficient 3 is positive. Equality is attained at \(\displaystyle x=3\).

Answer: \(f(x)\ge 7\)

(c)

\((x-3)^2=16\) gives both signs: \(\displaystyle x=3\pm 4\).

Answer: \(\left\{-1, 7\right\}\)

(d)

Complete the square, then use the vertex form and its positive leading coefficient.

\(34\)

Answer: \(34\).

Example 3 · Completing the square and quadratic turning points

For real x, \(f(x)=4 x^{2} - 32 x + 72\).

Diagram for this worked example
Read the description and labels. Geometric sketches are schematic unless coordinate scales are shown.
  1. Write f in completed-square form and state the vertex.
  2. State the range of f and justify it.
  3. Solve \(f(x)=24\).
  4. Find the y-intercept of the graph.
Show the reasoning

(a)

\(f(x)=4 \left(x - 4\right)^{2} + 8\) expands to the given expression. The square vanishes at \(\displaystyle x=4\).

Answer: \(4 \left(x - 4\right)^{2} + 8\); vertex \(\left( 4, \ 8\right)\)

(b)

The square is nonnegative and its coefficient 4 is positive. Equality is attained at \(\displaystyle x=4\).

Answer: \(f(x)\ge 8\)

(c)

\((x-4)^2=4\) gives both signs: \(\displaystyle x=4\pm 2\).

Answer: \(\left\{2, 6\right\}\)

(d)

Complete the square, then use the vertex form and its positive leading coefficient.

\(72\)

Answer: \(72\).

Common mistakes

Practise with answer checking

Original exam-style problems

Write complete solutions before opening the worked solution. The marking guidance rewards reasoning as well as answers.

Examination practice · 2020–2026

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