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Extracting a common algebraic factor — 0580

Take out the greatest numerical and variable factor from every term.

Core & Extended · Syllabus C2.2, E2.2

Notes and key methods

Factorising reverses expansion. The greatest common numerical factor uses a numerical HCF, while a common variable power uses its smallest exponent among the terms. Divide every term by the extracted factor to find what stays inside the bracket.

Expand the answer to check every coefficient and exponent. A factorisation is not complete when the remaining bracket still has a common factor. Taking out a negative factor changes every sign in its bracket.

Check the conditions

Three worked examples

Example 1 · Extracting a common algebraic factor

Consider \(E=10 x^{3} y + 15 x^{2} y^{2}\).

  1. Factorise E fully.
  2. Find the exponent of x in the greatest common monomial factor.
  3. After taking out \(5x^{2}y\), find the coefficient of y inside the bracket.
  4. Evaluate E at \(\displaystyle x=2, y=3\).
Show the reasoning

(a)

The numerical HCF is 5. The common variable factor is \(x^{2}y\). Dividing both terms by their product gives \(2 x + 3 y\).

Answer: \(5 x^{2} y \left(2 x + 3 y\right)\)

(b)

Use the HCF and the smallest variable exponents, dividing every original term by the complete common factor.

\(2\)

Answer: \(2\).

(c)

Use the HCF and the smallest variable exponents, dividing every original term by the complete common factor.

\(3\)

Answer: \(3\).

(d)

Use the HCF and the smallest variable exponents, dividing every original term by the complete common factor.

\(780\)

Answer: \(780\).

Example 2 · Extracting a common algebraic factor

Consider \(E=18 x^{4} y + 24 x^{3} y^{2}\).

  1. Factorise E fully.
  2. Find the exponent of x in the greatest common monomial factor.
  3. After taking out \(6x^{3}y\), find the coefficient of y inside the bracket.
  4. Evaluate E at \(\displaystyle x=2, y=3\).
Show the reasoning

(a)

The numerical HCF is 6. The common variable factor is \(x^{3}y\). Dividing both terms by their product gives \(3 x + 4 y\).

Answer: \(6 x^{3} y \left(3 x + 4 y\right)\)

(b)

Use the HCF and the smallest variable exponents, dividing every original term by the complete common factor.

\(3\)

Answer: \(3\).

(c)

Use the HCF and the smallest variable exponents, dividing every original term by the complete common factor.

\(4\)

Answer: \(4\).

(d)

Use the HCF and the smallest variable exponents, dividing every original term by the complete common factor.

\(2592\)

Answer: \(2592\).

Example 3 · Extracting a common algebraic factor

Consider \(E=2 x^{2} y + 4 x y^{2}\).

  1. Factorise E fully.
  2. Find the exponent of x in the greatest common monomial factor.
  3. After taking out \(2x^{1}y\), find the coefficient of y inside the bracket.
  4. Evaluate E at \(\displaystyle x=2, y=3\).
Show the reasoning

(a)

The numerical HCF is 2. The common variable factor is \(x^{1}y\). Dividing both terms by their product gives \(x + 2 y\).

Answer: \(2 x y \left(x + 2 y\right)\)

(b)

Use the HCF and the smallest variable exponents, dividing every original term by the complete common factor.

\(1\)

Answer: \(1\).

(c)

Use the HCF and the smallest variable exponents, dividing every original term by the complete common factor.

\(2\)

Answer: \(2\).

(d)

Use the HCF and the smallest variable exponents, dividing every original term by the complete common factor.

\(96\)

Answer: \(96\).

Common mistakes

Practise with answer checking

Original exam-style problems

Write complete solutions before opening the worked solution. The marking guidance rewards reasoning as well as answers.

Examination practice · 2020–2026

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