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Circle angles, cyclic quadrilaterals and tangents — 0580

Match the angle theorem to the same chord and the specified arc.

Extended · Syllabus E4.7

Notes and key methods

The angle at the centre subtended by a chord is twice the angle at the circumference on the same arc configuration. Angles subtended by the same chord in the same segment are equal. Opposite interior angles of a cyclic quadrilateral sum to 180°.

The angle between a tangent and a chord equals the angle in the alternate segment. Keep track of minor and reflex central angles: the appropriate doubled angle depends on which arc contains the circumference point. A radius to a tangent point is perpendicular to the tangent.

Check the conditions

Three worked examples

Example 1 · Circle angles, cyclic quadrilaterals and tangents

AB is a chord, O is the centre, and C and D are points on the major arc AB. The angle ACB is 56°. A tangent touches at A. Separately, P,Q,R,S in this order form a cyclic quadrilateral with interior angle \(\displaystyle P=76\)°.

  1. Find the minor angle AOB in degrees.
  2. Find angle OAB in degrees.
  3. Find the acute angle between the tangent at A and chord AB, in degrees.
  4. Find interior angle R of PQRS in degrees.
Show the reasoning

(a)

Use the centre-angle theorem with C on the major arc.

The same chord gives twice the circumference angle: 112°.

Answer: \(112\).

(b)

Use \(\displaystyle OA=OB\) and the triangle angle sum.

In isosceles triangle AOB, each base angle is \(\displaystyle \frac{180- 112}{2}= 34\)°.

Answer: \(34\).

(c)

Use the tangent-chord theorem with the appropriate acute angle.

The alternate-segment angle equals ACB=56°.

Answer: \(56\).

(d)

Identify P and R as opposite angles in the cyclic quadrilateral.

Opposite cyclic angles sum to 180°, giving 104°.

Answer: \(104\).

Example 2 · Circle angles, cyclic quadrilaterals and tangents

AB is a chord, O is the centre, and C and D are points on the major arc AB. The angle ACB is 57°. A tangent touches at A. Separately, P,Q,R,S in this order form a cyclic quadrilateral with interior angle \(\displaystyle P=77\)°.

  1. Find the minor angle AOB in degrees.
  2. Find angle OAB in degrees.
  3. Find the acute angle between the tangent at A and chord AB, in degrees.
  4. Find interior angle R of PQRS in degrees.
Show the reasoning

(a)

Use the centre-angle theorem with C on the major arc.

The same chord gives twice the circumference angle: 114°.

Answer: \(114\).

(b)

Use \(\displaystyle OA=OB\) and the triangle angle sum.

In isosceles triangle AOB, each base angle is \(\displaystyle \frac{180- 114}{2}= 33\)°.

Answer: \(33\).

(c)

Use the tangent-chord theorem with the appropriate acute angle.

The alternate-segment angle equals ACB=57°.

Answer: \(57\).

(d)

Identify P and R as opposite angles in the cyclic quadrilateral.

Opposite cyclic angles sum to 180°, giving 103°.

Answer: \(103\).

Example 3 · Circle angles, cyclic quadrilaterals and tangents

AB is a chord, O is the centre, and C and D are points on the major arc AB. The angle ACB is 58°. A tangent touches at A. Separately, P,Q,R,S in this order form a cyclic quadrilateral with interior angle \(\displaystyle P=78\)°.

  1. Find the minor angle AOB in degrees.
  2. Find angle OAB in degrees.
  3. Find the acute angle between the tangent at A and chord AB, in degrees.
  4. Find interior angle R of PQRS in degrees.
Show the reasoning

(a)

Use the centre-angle theorem with C on the major arc.

The same chord gives twice the circumference angle: 116°.

Answer: \(116\).

(b)

Use \(\displaystyle OA=OB\) and the triangle angle sum.

In isosceles triangle AOB, each base angle is \(\displaystyle \frac{180- 116}{2}= 32\)°.

Answer: \(32\).

(c)

Use the tangent-chord theorem with the appropriate acute angle.

The alternate-segment angle equals ACB=58°.

Answer: \(58\).

(d)

Identify P and R as opposite angles in the cyclic quadrilateral.

Opposite cyclic angles sum to 180°, giving 102°.

Answer: \(102\).

Common mistakes

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Original exam-style problems

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