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Stage 8 - Q1 - 2 marks
18877

Read the smallest journey time.

Stem
Leaves
1
2 5 8 8
2
1 4 7
3
1 4
4
0
Key: 2 | 3 means 23 minutes
Hint

Combine the first stem with its first ordered leaf.

Stage 8 - Q2 - 2 marks
18878

Find the modal journey time.

Stem
Leaves
1
2 5 8 8
2
1 4 7
3
1 4
4
0
Key: 2 | 3 means 23 minutes
Hint

Look for the most frequent complete value.

Stage 8 - Q3 - 2 marks
18879

Find the range of the journey times.

Stem
Leaves
1
2 5 8 8
2
1 4 7
3
1 4
4
0
Key: 2 | 3 means 23 minutes
Hint

Use the full largest and smallest values.

Stage 8 - Q4 - 2 marks
18880

Find the median journey time.

Stem
Leaves
1
2 5 8 8
2
1 4 7
3
1 4
4
0
Key: 2 | 3 means 23 minutes
Hint

Count leaves across all stems in order.

Stage 8 - Q5 - 3 marks
18881

What percentage of times exceed 25 minutes?

Stem
Leaves
1
2 5 8 8
2
1 4 7
3
1 4
4
0
Key: 2 | 3 means 23 minutes
Hint

Do not include a value merely because it is in the twenties row.

Stage 8 - Q6 - 3 marks
18882

What fraction of the times are at least 18 minutes?

Stem
Leaves
1
2 5 8 8
2
1 4 7
3
1 4
4
0
Key: 2 | 3 means 23 minutes
Hint

The phrase “at least” includes equality.

Stage 8 - Q7 - 4 marks
18883

Find the mean journey time.

Stem
Leaves
1
2 5 8 8
2
1 4 7
3
1 4
4
0
Key: 2 | 3 means 23 minutes
Hint

A leaf alone is not a data value.

Stage 8 - Q8 - 4 marks
18884

Remove the 40-minute observation. Find the new median and range.

Stem
Leaves
1
2 5 8 8
2
1 4 7
3
1 4
4
0
Key: 2 | 3 means 23 minutes
Hint

Both the number of observations and the largest value change.

Stage 8 - Q9 - 5 marks
18885

A pupil finds a mean within each stem row and then averages those four row means equally. Explain why this is unreliable and state the correct mean.

Stem
Leaves
1
2 5 8 8
2
1 4 7
3
1 4
4
0
Key: 2 | 3 means 23 minutes
Hint

A row mean must be weighted by its number of observations.

Stage 8 - Q10 - 6 marks
18886

An ordered diagram has values 16, 19,\(20+a\),\(20+b\), 28, 30, where a and b are digits with \(a\le b\). The mean is 23. Find every possible pair of missing leaves and show that the median is fixed.

Hint

Use the mean to constrain the leaf sum before listing possibilities.

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