0606 P12 - Mar 2023 - Q10 - 9 marks
(a) It is given that
\(2+\cos\theta=x,\qquad 1\lt x\lt 3\)
and
\(2\operatorname{cosec}\theta=y,\qquad y\gt 2.\)
Find \(y\) in terms of \(x\).
(b) Solve the equation
\(3\cos\frac{\phi}{2}=\sqrt3\sin\frac{\phi}{2}\)
for
\(-4\pi\lt \phi\lt 4\pi.\)
0606 P12 - Nov 2022 - Q4 - 5 marks
Solve the equation
\(3\sin\left(2x+\frac{\pi}{4}\right)=\sqrt3\cos\left(2x+\frac{\pi}{4}\right),\)
for \(0\leq x\leq\pi\).
0606 P13 - Nov 2022 - Q10 - 5 marks
Solve the equation
\(\sqrt2\cos(3x+1.2)=2\sin(3x+1.2),\)
where \(x\) is in radians, for \(-1.5\leq x\leq1.5\).
0606 P12 - Nov 2021 - Q4 - 4 marks
Solve the equation
\(\operatorname{cot}\left(2x+\frac{\pi}{3}\right)-\sqrt3=0,\)
where \(-\pi\lt x\lt \pi\) radians. Give your answers in terms of \(\pi\).
0606 P13 - Nov 2021 - Q3 - 5 marks
Solve the equation
\(\operatorname{cot}^2\left(2x-\frac{\pi}{3}\right)=\frac13,\)
where \(x\) is in radians and \(0\leq x\lt \pi\).
0606 P12 - Nov 2018 - Q1 - 4 marks
Solve \(1+\sqrt2\sin(x+50^\circ)=0\), for \(-180^\circ\leq x\leq180^\circ\).