Feb/Mar 2021 p12 q1
979
(a) Find the first three terms in the expansion, in ascending powers of \(x\), of \((1 + x)^5\).
(b) Find the first three terms in the expansion, in ascending powers of \(x\), of \((1 - 2x)^6\).
(c) Hence find the coefficient of \(x^2\) in the expansion of \((1 + x)^5 (1 - 2x)^6\).
Solution
(a) The binomial expansion of \((1 + x)^5\) is given by:
\(1 + 5x + \frac{5 \times 4}{2!}x^2 = 1 + 5x + 10x^2\).
(b) The binomial expansion of \((1 - 2x)^6\) is given by:
\(1 - 6(2x) + \frac{6 \times 5}{2!}(2x)^2 = 1 - 12x + 60x^2\).
(c) To find the coefficient of \(x^2\) in \((1 + x)^5 (1 - 2x)^6\), consider the products that result in \(x^2\):
- \(10x^2\) from \((1 + 5x + 10x^2) \times 1\)
- \(-60x^2\) from \(1 \times 60x^2\)
- \(60x^2\) from \(5x \times -12x\)
The coefficient of \(x^2\) is:
\(10 - 60 + 60 = 10\).
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