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June 2020 p13 q8
952
The first term of a progression is \(\sin^2 \theta\), where \(0 < \theta < \frac{1}{2}\pi\). The second term of the progression is \(\sin^2 \theta \cos^2 \theta\).
Given that the progression is geometric, find the sum to infinity.
Solution
The first term \(a = \sin^2 \theta\).
The second term \(ar = \sin^2 \theta \cos^2 \theta\).
Thus, the common ratio \(r = \cos^2 \theta\).
The sum to infinity of a geometric progression is given by:
\(S_\infty = \frac{a}{1-r}\)
Substitute \(a = \sin^2 \theta\) and \(r = \cos^2 \theta\):