Find the sum to infinity of the geometric progression with first three terms 0.5, 0.5^3 and 0.5^5.
Solution
The first term of the geometric progression is \(a = 0.5\).
The common ratio \(r\) is given by \(r = \frac{0.5^3}{0.5} = 0.5^2 = 0.25\).
The formula for the sum to infinity of a geometric progression is \(S_\infty = \frac{a}{1 - r}\).
Substitute the values of \(a\) and \(r\):
\(S_\infty = \frac{0.5}{1 - 0.25} = \frac{0.5}{0.75} = \frac{2}{3}\).
Thus, the sum to infinity is \(\frac{2}{3}\) (or 0.667).
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