For the arithmetic progression P, the 5th term is given by:

\(a + 4d.\)

For the arithmetic progression Q, the 12th term is given by:

\(2(a + 1) + 11(d + 1).\)

Using the given ratio:

\(\frac{a + 4d}{2(a + 1) + 11(d + 1)} = \frac{1}{3}.\)

Cross-multiplying gives:

\(3(a + 4d) = 2(a + 1) + 11(d + 1).\)

Simplifying, we get:

\(a + d = 13.\)

For the sum of the first 5 terms of P:

\(\frac{5}{2}(2a + 4d).\)

For the sum of the first 5 terms of Q:

\(\frac{5}{2}(4(a + 1) + 4(d + 1)).\)

Using the given ratio:

\(\frac{\frac{5}{2}(2a + 4d)}{\frac{5}{2}(4(a + 1) + 4(d + 1))} = \frac{2}{3}.\)

Cross-multiplying gives:

\(3(2a + 4d) = 2(4(a + 1) + 4(d + 1)).\)

Simplifying, we get:

\(-a + 2d = 8.\)

Solving the equations \(a + d = 13\) and \(-a + 2d = 8\) simultaneously, we find:

\(d = 7\) and \(a = 6\).