The gradient of the normal to a curve at the point with coordinates \((x,y)\) is given by \(\dfrac{\sqrt x}{1-3x}\).

(i) Find the equation of the curve, given that the curve passes through the point \((1,-10)\).

(ii) Find, in the form \(y=mx+c\), the equation of the tangent to the curve at the point where \(x=4\).