0606 P21 - Nov 2017 - Q7 - 6 marks
8655
Find \(y\) in terms of \(x\), given that \(\dfrac{d^2y}{dx^2}=6x+\dfrac2{x^3}\) and that when \(x=1\), \(y=3\) and \(\dfrac{dy}{dx}=1\).
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