Let the first term be \(a\) and the common difference be \(d\).

The fifth term of the arithmetic progression is given by:

\(a + 4d = 18\)

The sum of the first 5 terms is given by:

\(\frac{5}{2} (2a + 4d) = 75\)

Solving the first equation for \(a\):

\(a = 18 - 4d\)

Substitute \(a = 18 - 4d\) into the sum equation:

\(\frac{5}{2} (2(18 - 4d) + 4d) = 75\)

\(\frac{5}{2} (36 - 8d + 4d) = 75\)

\(\frac{5}{2} (36 - 4d) = 75\)

\(5(36 - 4d) = 150\)

\(180 - 20d = 150\)

\(30 = 20d\)

\(d = \frac{3}{2}\)

Substitute \(d = \frac{3}{2}\) back into \(a = 18 - 4d\):

\(a = 18 - 4 \times \frac{3}{2}\)

\(a = 18 - 6\)

\(a = 12\)

Thus, the first term is 12, and the common difference is \(\frac{3}{2}\).